Конструирование агрегатов самолета

48 Исходные данные : 1 2 1 2 3 4 1 2 3 1 1 2 2 900 H; 3, 0 м ; 1,5 м ; 0,5 м ; H 1, 0 м ; 1, 0 м ; 0,5 м ; 200 ; м H H H 266, 67 ; 400 ; 266, 67 ; м м м H H 66, 67 ; 200 . м м k k k P L L L l l l l q q q q q q q q q q = = = = = = = = = = = = ∆ = − = ∆ = − = Расчет : ( ) 3 3 3 3 1 2 1 2 2 2 1 2 2 2 3 3 3 2 2 2 2 1 1 1 1 2 2 2 ; 4 15 4 15 200 0,5 66,67 0,5 , 2 2 3 2 2 3 к к к q L q L q L q L M l M l l M l q l q l M     + + + = − + − +         ⋅ ⋅ = + = + ⋅ ⋅ △ △ △ М 1 = М 3 так как балка симметричная . ( ) 2 2 2 2 1 2 1 1 2 2 1 3 1 1 1 2 2 2 2 2 2 2 2 200 1,5 2 200 1,5 27, 78 1 2 1 1 27, 78 1 4 15 200 1, 5 2 200 1,5 ; 4 15 14 200 1, 5 200 1,5 300; 2 2 3 2 1 2 3 1 300 H; 300 3, 265 м ; H; 2 H к к q L q L R l l R R L q L l R M l M   ⋅ ⋅ ⋅ ⋅ + + + ⋅ = − + −       ⋅ ⋅ ⋅ − +     = − ⋅ ⋅ ⋅ ⋅ ′ = + = + = ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ′ ′ = =   −     ′ = + ⋅ △ △ 2 1 1 1 2 2 2 3 q L L l l   ⋅ − =   ⋅  